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3*10^2x=3600
We move all terms to the left:
3*10^2x-(3600)=0
Wy multiply elements
30x^2-3600=0
a = 30; b = 0; c = -3600;
Δ = b2-4ac
Δ = 02-4·30·(-3600)
Δ = 432000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{432000}=\sqrt{14400*30}=\sqrt{14400}*\sqrt{30}=120\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120\sqrt{30}}{2*30}=\frac{0-120\sqrt{30}}{60} =-\frac{120\sqrt{30}}{60} =-2\sqrt{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120\sqrt{30}}{2*30}=\frac{0+120\sqrt{30}}{60} =\frac{120\sqrt{30}}{60} =2\sqrt{30} $
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